Solve the system of equations \( \begin{align*} 4x+2y & = 23, \\ -x+3y & = 4. \end{align*}\)
\(\begin{pmatrix} 4&2&|&23\\ -1&3&|&4\\ \end{pmatrix}\\\sim\begin{pmatrix} 0&14&|&39\\ -1&3&|&4\\ \end{pmatrix}\\ y = \dfrac{39}{14}\\ -x + 3\left(\dfrac{39}{14}\right) = 4\\ x = \dfrac{61}{14}\)
THX!!!!!!!!!!
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