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Help.

 Dec 8, 2017
 #1
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(3p^2 + 5pq-q^2 )    + (p^2 + 3pq  - 2q^2 )   =

 

3p^2 + p^2 +  5pq + 3pq - q^2 - 2q^2 =

 

4p^2  +  8pq   - 3q^2  

 

 

27x^3  +  64            this is a difference of two cubes

 

( 3x +  4)   ( ( 3x)^2  - (3x * 4)  + 4^2)    =

 

(3x + 4)  (  9x^2  -  12x   +  16)

 

 

 

cool cool cool

 Dec 8, 2017

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