Two parabolas are the graphs of the equations $y=2x^2-10x-10$ and $y=x^2-4x+6$.. Give all points where they intersect. List the points in order of increasing $x$-coordinate, separated by semicolons.
Equate the "y's"
2x^2 - 10x - 10 = x^2 - 4x + 6 rearrange as
x^2 - 6x - 16 = 0 factor
(x - 8) ( x + 2) = 0
Set both factors to 0 and solve for x and we have that x = -2 and x = 8
So....when x = - 2, y = (-2)^2 - 4(-2) + 6 = 18
And when x = 8, y = (8)^2 -4(8) + 6 = 38
So
(-2, 18) ; (8, 38)