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As x ranges over all real numbers, whatare the possible values of y = (x^2 + 2)/(2x^2 + 1)?

 May 17, 2020
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Because of the x2 terms, there will be no negative values.

The smallest value will occur when x = 0   --->   (02 + 2)(2·02 + 1)  =  2·1  =  2

 May 18, 2020

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