A circle has a radius of 10. A chord of distance 16 is drawn inside the circle. What is the distance from the center of the circle to the chord? I don't understand.
Let O be the center of the circle.
Let CD be the chord of length 16
Let AOB be the diameter of the circle that is the perpendicular bisector of the chord; A is on minor arc(CD)
and D is on major arc(CD).
Let the point of intersection of AOB and CD be point X.
Being a radius, OD = 10.
XD = 8.
Triangle(OXD) is a right triangle. OX2 + XD2 = OD2
OX2 + 82 = 102
OX2 + 64 = 100
OX2 = 36
OX = 6
OX is the distance from the center to the chord.