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 Mar 7, 2017
 #1
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[ 3y - 8 ] / 12 = y / 5     cross-multiply

 

5 [3y - 8 ] = 12y      simpify

 

15y - 40  = 12y      add 40 to both sides. subtract 12y from both sides

 

3y  = 40       divide both sides by 3

 

y  = 40 / 3

 

 

cool cool cool

 Mar 7, 2017
 #2
avatar+956 
+5

I know this has question has been answered, but I wanted to show you this neat trick I use for cross multiplying: 

For Example: 8/4=x/10

For this I would use a method called the oval circle method: 

Basically you oval a diagonal with only numbers no letters and circle the remaining number. And the letter will go

as your x=. So we oval 8 and 10 and circle 4. And we make x as x=. And we plug into the formula: x=aXb/c 

So it becomes x= 8 X 10/4

x=80/4

x=20.

But I suppose it wont work for this problem, but it's extremely simple and easy way to do it.  

 Mar 7, 2017

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