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The quadratic $2x^2+5x+12=19-7x$ has two solutions. What is the positive difference between these solutions?

 
Guest Jun 17, 2017
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 #1
avatar+25683 
+2

As follows:

 

\(2x^2+5x+12=19-7x\rightarrow 2x^2+12x-7=0\\ \text{ use the quadratic formula to find x } x= \frac{-12\pm \sqrt{12^2+4\times 2\times 7}}{2\times2}\\ x = \frac{-12\pm\sqrt{200}}{4}\\ \text{ positive difference: }\sqrt{200}/2\rightarrow 5\sqrt2\)

 
Alan  Jun 17, 2017
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1+0 Answers

 #1
avatar+25683 
+2
Best Answer

As follows:

 

\(2x^2+5x+12=19-7x\rightarrow 2x^2+12x-7=0\\ \text{ use the quadratic formula to find x } x= \frac{-12\pm \sqrt{12^2+4\times 2\times 7}}{2\times2}\\ x = \frac{-12\pm\sqrt{200}}{4}\\ \text{ positive difference: }\sqrt{200}/2\rightarrow 5\sqrt2\)

 
Alan  Jun 17, 2017

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