The vertex is at (5,-4) and it is sideways so
It appears to pass through (3,-2)
\((-2+4)^2=k(3-5)\\ 4=k*(-2)\\ k=-2\\ (y+4)^2=-2(x-5)\\\)
That is the formula
So the question does not make much sense
I mean x=ay^2+by+c. Find a+b+c
How would I rearrange it? Sorry to bother you...
can i have the answer
No, you cannot have the answer. I have already done the hard part.
If you cannot finish it then your teacher needs to know.
It means you are in the wrong class or she/he is teaching at an inappropriate level.
You rearrange it by expanding both sides separately.
And then take everything over to one side and put it equal 0.