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How many square units are in the area of the convex quadrilateral with vertices

\(P_1(0, 0), P_2(3, 0), P_3(2, 2)\ and\ P_4(0, 3)?\)

Hello Guest!

\(A=A_{tra}+A_{tri}\)

\(A_{tra}=\frac{1}{2}\cdot (y_2+y_3)\cdot x_3=\frac{1}{2}\cdot(3+2)\cdot 2=\color{blue}5\)

\(A_{tri}=\frac{1}{2}\cdot y_3\cdot (x_4-x_3)=\frac{1}{2}\cdot 2\cdot (3-2)=\color{blue}1\)

\(A=A_{tra}+A_{tri}=5+1=\color{blue}6\)

The area of the convex quadrilateral has 6 square units.

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