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# Help

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How many square units are in the area of the convex quadrilateral with vertices (0, 0), (3, 0), (2, 2) and (0, 3)?

Feb 1, 2021

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How many square units are in the area of the convex quadrilateral with vertices

$$P_1(0, 0), P_2(3, 0), P_3(2, 2)\ and\ P_4(0, 3)?$$

Hello Guest!

$$A=A_{tra}+A_{tri}$$

$$A_{tra}=\frac{1}{2}\cdot (y_2+y_3)\cdot x_3=\frac{1}{2}\cdot(3+2)\cdot 2=\color{blue}5$$

$$A_{tri}=\frac{1}{2}\cdot y_3\cdot (x_4-x_3)=\frac{1}{2}\cdot 2\cdot (3-2)=\color{blue}1$$

$$A=A_{tra}+A_{tri}=5+1=\color{blue}6$$

The area of the convex quadrilateral has 6 square units.

!

Feb 1, 2021
edited by asinus  Feb 1, 2021