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Find n if n > 2 and (n!)^2 *(n^2 - 2)! = 5/6*(n^2)!*(((n - 2)!)^2.

 Dec 19, 2019
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a=3; c= (a!)^2 *(a^2 - 2)! ; d=5/6*(a^2)!*(((a - 2)!)^2;if(c==d, goto4, goto5);printc,d, a; a++;if(a<100, goto1, 0)

 

OUTPUT:  n = 11

 Dec 19, 2019

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