In triangle ABC, M is the midpoint of AB. Let D be the point on BC such that AD bisects angleBAC and let the perpendicular bisector of AB intersect AD at P. If AB=36 and MP=9, then find the distance from P to line AC
The distance from P to line AC is sqrt(18^2 - 9^2) = 9*sqrt(3).
I forgot to divide by 3, so the distance is 3*sqrt(3).
