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In triangle ABC, M is the midpoint of AB. Let D be the point on BC such that AD bisects angleBAC and let the perpendicular bisector of AB intersect AD at P. If AB=36 and MP=9, then find the distance from P to line AC 

 Nov 23, 2019
 #1
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The distance from P to line AC is sqrt(18^2 - 9^2) = 9*sqrt(3).

 Nov 23, 2019
 #2
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I forgot to divide by 3, so the distance is 3*sqrt(3).

Guest Nov 23, 2019

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