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# help

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Simplify (x^2 - 25)/(x^2 + 10x + 25).

Nov 15, 2019

#1
+470
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To simplify polynomial fractions, you can factor and find canceling x-intercepts.

$$x^2-25 \over x^2+10x + 25$$can be factored in both the numerator and denominator. $$x^2 -25$$ becomes $$(x+5)(x-5)$$, and

$$x^2+10x+25$$ becomes $$(x+5)(x+5)$$.

From there you can get $$(x+5)(x-5) \over (x+5)(x+5)$$.

You can then eliminate one $$x+5$$ from each part of the fraction, resulting in $$x-5 \over x+5$$.

If no obvious factors are there, you can always use the quadratic formula to find them when the highest power is 2.

Hope this helps!

Nov 15, 2019
#2
+58
+2

Guest, here are some easy identities for simplifying quadratics.

First, if a quadratic is in the form a^2 - b^2, then the form of the factored equation would be (a+b)(a-b). This is called the difference of squares.

Second, if in the normal quadratic form of ax ^2 + bx + c, then one must find a number that adds up to b, and multiplies to c. If a is a coefficient of a > 1, then one must find a number that adds to b and multiplies to ac.

Hope this helps!

BasicMaths

Nov 15, 2019
#3
+105370
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THX, ZZZZZZ and BasicMaths.....!!!!!!

Nov 15, 2019