#1**+3 **

To simplify polynomial fractions, you can factor and find canceling x-intercepts.

\(x^2-25 \over x^2+10x + 25\)can be factored in both the numerator and denominator. \(x^2 -25 \) becomes \((x+5)(x-5)\), and

\(x^2+10x+25\) becomes \((x+5)(x+5)\).

From there you can get \((x+5)(x-5) \over (x+5)(x+5)\).

You can then eliminate one \(x+5\) from each part of the fraction, resulting in \(x-5 \over x+5\).

If no obvious factors are there, you can always use the quadratic formula to find them when the highest power is 2.

Hope this helps!

ZZZZZZ Nov 15, 2019

#2**+2 **

Guest, here are some easy identities for simplifying quadratics.

First, if a quadratic is in the form **a^2 - b^2**, then the form of the factored equation would be **(a+b)(a-****b)**. This is called the difference of squares.

Second, if in the normal quadratic form of **a****x ^2 + bx + c**, then one must find a number that adds up to b, and multiplies to c. If a is a coefficient of a > 1, then one must find a number that adds to b and multiplies to ac.

Hope this helps!

BasicMaths

BasicMaths Nov 15, 2019