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For how many integer values of  between 1 and 1000 inclusive does the decimal representation of  terminate?

Guest Oct 6, 2018
 #1
avatar+2389 
+1

You must not be asking this correctly.

 

The decimal representation for any integer terminates.  They have no non-zero digits to the right of the decimal point at all.

Rom  Oct 6, 2018
 #2
avatar+93658 
+1

well there is just one integer between 1 and 3  that is the number 2

there are 5 integers between 1 and 7 they are  2,3,4,5,6

 

So there must be  1000-1-1 = 998 integers BETWEEN 1 and 1000.

Melody  Oct 6, 2018
 #3
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This is clearly not what the guest asked, his question is missing something. Why did you mark this with a checkmark?

Guest Oct 6, 2018
 #6
avatar+93658 
0

I think this is the best interpretation for this question. 

But yes it is, at best, a poorly written question and it has been answered.

 

It looks like it has been through an interpreter and the interpreter has not worked adequately.

Melody  Oct 6, 2018
 #7
avatar+2389 
0

I think it was probably meant to be asked has how many integers

\(1 \leq n \leq 1000\) does the decimal representation of \(\dfrac 1 n\) terminate.

Rom  Oct 7, 2018
 #8
avatar+93658 
0

Yes that is quite possible  :)

Melody  Oct 7, 2018

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