help!!!

\(5^{2x+3}=6^{x+1} \\ (2x+3)\log(5)=(x+1)\log(6) \\ (2\log(5)-\log(6))x=\log(6)-3\log(5) \\ x = \dfrac{\log(6)-3\log(5)}{2\log(5)-\log(6)}\)

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 5^(2x+3)=6^(x+1)

x= -2.12775521496