y-5=1/3(x-(-4)
\(y-5=\frac{1}{3(x-(-4))}\) is that right?
\(y-5=\frac{1}{3(x+4)}\)
\(y-5=\frac{1}{3x+12}\)
\(y=5+\frac{1}{3x+12}\) !
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