If 2 and 3 are the roots of the polynomial 3x^2 - 2kx + 2m=0 then find the value of m.
(3x-9)(x-2) = 0
3x^2 -15x + 18 = 0 m = 9
(3x-6)(x-3) = 0
By Vieta
In the form ax^2 + bx + c
The product of the roots = c /a = (2m) / 3
So
2 * 3 = 2m / 3
6 = 2m / 3
18 = 2m
m = 9
+36916 
