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If 2 and 3 are the roots of the polynomial 3x^2 - 2kx + 2m=0 then find the value of m.

 Jan 8, 2020
 #1
avatar+19815 
+2

(3x-9)(x-2) = 0

3x^2 -15x + 18 = 0      m = 9

 

(3x-6)(x-3) = 0

3x^2 -15x + 18 = 0      m = 9 

 Jan 8, 2020
 #2
avatar+106519 
+1

By Vieta

 

In the form   ax^2 + bx + c

 

The product of the roots =   c /a   =     (2m) / 3

 

So

 

2 * 3  =  2m / 3

 

6  =  2m  / 3

 

18  = 2m

 

m  = 9

 

cool cool cool

 Jan 8, 2020

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