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What is the minimum possible value for y in the equation y = x^2 + 12x + 5?

 Oct 22, 2019
 #1
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The min wil occur  when  x  = -12 / [2 * 1]  = -12.2  = -6

 

So.......the min for y will be

 

 

(-6)^2  + 12(-6)  + 5  =

 

36   -  72   + 5  =

 

-36  + 5  =

 

-31

 

 

cool cool cool

 Oct 22, 2019

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