What is the minimum possible value for y in the equation y = x^2 + 12x + 5?
The min wil occur when x = -12 / [2 * 1] = -12.2 = -6
So.......the min for y will be
(-6)^2 + 12(-6) + 5 =
36 - 72 + 5 =
-36 + 5 =
-31
