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Given the digits 1, 2, 2, 3, 3, 3, how many 4-digit numbers can we build from these digits?

 Jul 6, 2020
 #1
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You have 5 distinct combinations. 
(1,2,2,3),  (1,2,3,3),  (1,3,3,3),  (2,2,3,3),  (2,3,3,3)
Each combination has the following number of permutations: [4!/2! + 4!/2! + 4!/3! + 4!/2!2! + 4!/3!]=12 + 12 + 4 + 6 + 4 = 38 permutations.

 Jul 6, 2020

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