Line l1 represents the graph of 3x + 4y = -14. Line l2 passes through the point (-5,7), and is perpendicular to line l1. If line l2 represents the graph of y=mx +b, then find m+b.
Isolate y in 3x + 4y = -14 ==> y = 3x/4 - 14/4
Slope of Perpendicular = -4/3, point-slope form of equation y - 7 = -4/3(x + 5)
==> 3y - 21 = -4(x + 5) = -4x + 20
==> 3y = -4x + 41
==> y = -4/3*x + 41/3
m + b = -4/3 + 41/3 = 37/3
+231 
