+0  
 
0
55
1
avatar+176 

What is the probability that at least two of the faces match when you roll three fair six-sided dice? Express your answer as a common fraction.

 

This seems easy, but the *at least* makes it harder, all I understand is with the at least you need to subtract a certain probability from 1 xd

 Dec 5, 2018
 #1
avatar
+1

First die: Any number
2nd die : probability that it is different from the first = 5/6
3rd die:  probability that it is different from the first two dice=4/6
So, the probability of getting a matching pair is:
1 -[6/6 x 5/6 x 4/6]=1 - 120/216 =96/216 = 12/27 = 44.44%
Note: This is the same as getting one particular pair(say 2 ones), which gives you the probability of 2/27. But you have 6 numbers that can be matched as pairs(11, 22, 33, 44, 55, 66). So:2/27 x 6 =12/27 =44.44%

 Dec 6, 2018

6 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.