Let \(f(x) = \begin{cases} 3x^2 + 2&\text{if } x\le 3, \\ ax - 1 &\text{if } x>3. \end{cases} \)Find a if the graph of y=f(x) is continuous (which means the graph can be drawn without lifting your pencil from the paper).
When x = 3 3x^2+2 = 29
ax-1 = 29 when x = 3
a(3) = 30
a = 10