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Let \(f(x) = \begin{cases} 3x^2 + 2&\text{if } x\le 3, \\ ax - 1 &\text{if } x>3. \end{cases} \)Find a if the graph of y=f(x) is continuous (which means the graph can be drawn without lifting your pencil from the paper).

 Jul 25, 2020
 #1
avatar+28021 
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When x = 3      3x^2+2 = 29

 

ax-1 = 29    when x = 3

a(3) = 30

a = 10

 Jul 25, 2020

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