+0  
 
0
866
5
avatar+2496 

Excuse me for writings !

 Jan 7, 2016

Best Answer 

 #4
avatar+2496 
+5

Thanks CPhill !

 Jan 7, 2016
 #1
avatar
+5

To: Solveit:

I copied your very interesting question of this morning, about faculty, just a few questions below this one. I posted my answer to it. Please look at it. Sometimes simple logic in concrete words and numbers is a much better solution than abstract symblic Algebra. Thanks.

 Jan 7, 2016
 #2
avatar+2496 
+5

Thanks Guest really ! 

 Jan 7, 2016
edited by Solveit  Jan 7, 2016
 #3
avatar+111328 
+5

Call the radius of the circle, r.

 

The area of the surrounding square, ABCD = 4r^2

The area of the square inscribed in the circle = 2r^2

The area of the circle = pi*r^2

 

So.....the shaded area = the area of the circle - the area of the inscribed square =  [pi*r^2 -2r^2]

 

So....the probability  that  a point is chosen in the shaded area  = 

 

shaded area  / total area bounded by ABCD =

 

[pi *r^2 - 2r^2] / [4r^2]  =

 

r^2 [ pi - 2]/ {r^2 *4]  =   [  r^2  cancels ]

 

[pi - 2 ] / 4        (E)

 

 

 

cool cool cool

 Jan 7, 2016
 #4
avatar+2496 
+5
Best Answer

Thanks CPhill !

Solveit Jan 7, 2016
 #5
avatar+111328 
0

No prob, Solveit.....!!!!

 

 

cool cool cool

 Jan 7, 2016

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