+0  
 
0
270
5
avatar+2493 

Excuse me for writings !

Solveit  Jan 7, 2016

Best Answer 

 #4
avatar+2493 
+5

Thanks CPhill !

Solveit  Jan 7, 2016
Sort: 

5+0 Answers

 #1
avatar
+5

To: Solveit:

I copied your very interesting question of this morning, about faculty, just a few questions below this one. I posted my answer to it. Please look at it. Sometimes simple logic in concrete words and numbers is a much better solution than abstract symblic Algebra. Thanks.

Guest Jan 7, 2016
 #2
avatar+2493 
+5

Thanks Guest really ! 

Solveit  Jan 7, 2016
edited by Solveit  Jan 7, 2016
 #3
avatar+78577 
+5

Call the radius of the circle, r.

 

The area of the surrounding square, ABCD = 4r^2

The area of the square inscribed in the circle = 2r^2

The area of the circle = pi*r^2

 

So.....the shaded area = the area of the circle - the area of the inscribed square =  [pi*r^2 -2r^2]

 

So....the probability  that  a point is chosen in the shaded area  = 

 

shaded area  / total area bounded by ABCD =

 

[pi *r^2 - 2r^2] / [4r^2]  =

 

r^2 [ pi - 2]/ {r^2 *4]  =   [  r^2  cancels ]

 

[pi - 2 ] / 4        (E)

 

 

 

cool cool cool

CPhill  Jan 7, 2016
 #4
avatar+2493 
+5
Best Answer

Thanks CPhill !

Solveit  Jan 7, 2016
 #5
avatar+78577 
0

No prob, Solveit.....!!!!

 

 

cool cool cool

CPhill  Jan 7, 2016

6 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details