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(tan(asin(.2))^2 = 0.0416666666666946

Let x = tan(arcsin(0.2)).  Compute x^2.

Let 

\(\theta=asin(\frac{1}{5})\\ \theta \text{ is in the 1st or 2nd quadrant}\\ \text{Draw a right angled triangle for the first quadrant version}\\ \text{opp=1, hypotenuse=5, adj=} \sqrt{24}\\ x=tan\theta =\pm \frac{1}{\sqrt{24}}\\ x^2=\frac{1}{24} \)

LaTex:

 quadrant version}\\ \text{opp=1, hypotenuse=5, adj=} \sqrt{24}\\ x=tan\theta =\pm \frac{1}{\sqrt{24}}\\ x^2=\frac{1}{24}