\(D\) is on side \(\overline {AB}\) of \(\triangle ABC.\) We know \(\triangle ABC \sim \triangle ACD\) and \(\angle A =48^\circ.\) If \(BC=BD,\) what is \(\angle B\) in degrees?
Angle B = 58 degrees.
Triangles ABC and ACD are the right-angled triangles.
Angle B = 42º
