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What is the area of the region of the plane determined by the inequality 3 <= |x| + |y| <= 4?

 Nov 26, 2019
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See the graph here :  https://www.desmos.com/calculator/s42iuonkkh

 

The overlap of these areas  what we want.....  this is  the area of a square with a side of 4  less the area of a square with a side of 3

 

So....the area of interest  is 4^2  - 3^2   =  16 - 9   =    7 units^2

 

 

cool cool cool

 Nov 26, 2019

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