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Compute (1 - 1/4)(1 - 1/9)(1 - 1/16) ... (1 - 1/k^2) ... (1 - 1/10000).

 May 23, 2020
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∏[1 - 1/n^2], n, 2, 100 =101 / 200

 May 23, 2020

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