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The distance between the points (x, 21) and (4, 7) is 10√2. Find the sum of all possible values of x.

 Sep 19, 2020
 #1
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The sum of all possible values of is 28.

 Sep 19, 2020
 #2
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The distance between the points (x, 21) and (4, 7) is 10√2. Find the sum of all possible values of x.

 

10√2  is a hypotenuse of a right triangle, the longer leg is 14.                                                                                          The short leg     a = sqrt[(10√2)2 - 142] = 2

 

1/      x = 4 - a = 2

 

2/      x = 4 + a = 6

 

So, the sum of all possible values of x is 8 smiley

 Sep 20, 2020
edited by jugoslav  Sep 20, 2020

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