+47 Leslie said that a circle with equation (x - 2)2 + (y - 7)2 = 13 has a tangent line represented by "y - 5 = -3/2(x + 1)". Right or wrong?
+128566 (x -2)^2 + (y - 7)^2 = 13
The center = ( 2, 7)
y = (-3/2)(x + 1) + 5
This would mean the the point ( -1, 5) is on the circle (which is true) because (-1-2)^2 + (5-7)^2 =
3^2 + 2^2 = 13
It also means that the slope of the line containing the center and this point is
[ 7-5] / [ 2 - -1] = 2/3
The tangent line line at (-1.5) would have a slope of -3/2
Looks like Leslie is correct !!!
