1 - The word B, A, N, A, N, A =6! / 3!.2! =60 permutations. Since each permutations begins with one of the 6 letters, or 60 / 6 = 10 permutations for each letter. Therefore, you will have 60 - 10 =50 permutations without the letter "B" at the beginning of the permutations.
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