Find the equation of the line passing through (2,-2) that is perpendicular to the line 4x + 5y = 1.
+781 We write 4x+5y=1 in slope intercept form.
4x+5y=1
5y=-4x+1
y=-4/5x+1/5
The slope of perpendicular line must be 5/4. We know it is y=5/4x+b. We plug in the given point to find b.
y=5/4x+b
-2=5/4(2)+b
=-2=10/4+b
=b=-9/2.
Therefore the equation is y=5/4x-9/2.
