Two vertices of a regular pentagon, in red, intersect with two vertices of a regular hexagon, in blue. What is the measure of the yellow angle?
The formula for each interior angle of a regular polygon of n sides is: (n - 2)(180o)/n
For a regular hexagon: (6 - 2)(180o)/6 = 120o.
For a regular pentagon: (5 - 2)(180o)/5 = 108o.
For the red triangle that is outside the blue hexagon, the two base angles are each:
(180o - 108o) / 2 = 36o.
This means that each base angle of the dark-red trapezoid is 108o - 36o = 72o.
Subtracting this from the hexagon angle, we get 120o - 72o = 48o
The formula for each interior angle of a regular polygon of n sides is: (n - 2)(180o)/n
For a regular hexagon: (6 - 2)(180o)/6 = 120o.
For a regular pentagon: (5 - 2)(180o)/5 = 108o.
For the red triangle that is outside the blue hexagon, the two base angles are each:
(180o - 108o) / 2 = 36o.
This means that each base angle of the dark-red trapezoid is 108o - 36o = 72o.
Subtracting this from the hexagon angle, we get 120o - 72o = 48o