The Whoopis are playing a 44 game season. Each game results in a win or a loss, and cannot end in a tie. So far, they have 20 wins and 15 losses. In order to make the playoffs, they must win at least 60% of all of their games. What is the smallest number of their remaining games that they must win to make the playoffs?
+781 We let x represent the number of games won. The number of games they have left to play are 44-(20+15)=9.
Then
\(\frac{20+x}{44}\geq3/5\)
20+x is the number of games won.
We then solve.
\(\frac{20+x}{44}\geq\frac{3}{5}\\ 100+5x\geq132\\ 5x\geq32\\ \)
Then the smallest x can be is \(\boxed{7}\).
