If 8^x = (1/2)^(x + 1), what is the value of x?
(1/2)^(x + 1) = 2^(-x-1)
8^x = 2^3x
3x = -x-1
x = -1/4
Log both sides
x log8 = (x+1) log 1/2
1.2041998 x = -.30102999
x = - .25
( but I like possible's method more!)