Find the number of integers n, 1 < n < 2014, such that 8n/(9999 - n) is also an integer.
For n between 1 and 2014, I could only find one value for n. However, if n is between 1 and 9999, there are well over 40 integers that satisfy your conditions.
n =1,111.
8 x 1,111 =8,888
9999 - 1111 =8,888
So, 8,888 / 8,888 = 1
