Let X be the point one unit to the right of B and one unit above A.
Angle(DBX) = tan-1(1/3) = 18.435o (approximately)
Angle(CAX) = tan-1(1/2) = 26.565o (approximately).
The quadrilateral(BXAE) contains 360o in its interior angles.
In the quadrilateral, angle(AXB) = 270o.
In the quadrilateral: angle(AEB) + angle(DBX) + angle(CAX) + angle(AXB) = 360o
angle(AEB) + 18.435o + 26.565o + 270o. = 360o
angle(AEB) = 46o