Suppose that $a$, $b$, and $c$ are real numbers such that $\frac{a}{b} = \frac{\sqrt{10}}{\sqrt{21}}$ and $\frac{b}{c} = \frac{\sqrt{135}}{\sqrt{8}}$. Find $\frac{a}{c}$. Completely simplify and rationalize the denominator.
\(\frac{a}{b}\,=\,\frac{\sqrt{10}}{\sqrt{21}} \qquad\text{so}\qquad a\,=\,\frac{b\sqrt{10}}{\sqrt{21}}\\~\\ \frac{b}{c}\,=\,\frac{\sqrt{135}}{\sqrt8}\qquad\text{so}\qquad c\,=\,\frac{b\sqrt{8}}{\sqrt{135}} \\~\\ \ \\~\\\frac{a}{c}\,=\,(\frac{b\sqrt{10}}{\sqrt{21}})\,/\,(\frac{b\sqrt{8}}{\sqrt{135}}) \,=\,(\frac{b\sqrt{10}}{\sqrt{21}})(\frac{\sqrt{135}}{b\sqrt{8}}) \,=\,(\frac{\sqrt{10}}{\sqrt{21}})(\frac{\sqrt{135}}{\sqrt{8}}) \\~\\ \frac{a}{c}\,=\,\frac{\sqrt{10\,\cdot\,135}}{\sqrt{21\,\cdot\,8}} \,=\,\frac{\sqrt{2\cdot5\cdot5\cdot3\cdot3\cdot3}}{\sqrt{3\cdot7\cdot2\cdot2\cdot2}} \,=\,\frac{\sqrt{2}\cdot\sqrt{5\cdot5}\cdot\sqrt{3\cdot3}\cdot\sqrt{3}}{\sqrt{3}\cdot\sqrt{7}\cdot\sqrt{2\cdot2}\cdot\sqrt{2}} \,=\,\frac{\sqrt{5\cdot5}\cdot\sqrt{3\cdot3}}{\sqrt{7}\cdot\sqrt{2\cdot2}} \\~\\ \frac{a}{c}\,=\,\frac{5\,\cdot\,3}{2\sqrt{7}} \,=\,\frac{15\sqrt7}{14} \)
.\(\frac{a}{b}\,=\,\frac{\sqrt{10}}{\sqrt{21}} \qquad\text{so}\qquad a\,=\,\frac{b\sqrt{10}}{\sqrt{21}}\\~\\ \frac{b}{c}\,=\,\frac{\sqrt{135}}{\sqrt8}\qquad\text{so}\qquad c\,=\,\frac{b\sqrt{8}}{\sqrt{135}} \\~\\ \ \\~\\\frac{a}{c}\,=\,(\frac{b\sqrt{10}}{\sqrt{21}})\,/\,(\frac{b\sqrt{8}}{\sqrt{135}}) \,=\,(\frac{b\sqrt{10}}{\sqrt{21}})(\frac{\sqrt{135}}{b\sqrt{8}}) \,=\,(\frac{\sqrt{10}}{\sqrt{21}})(\frac{\sqrt{135}}{\sqrt{8}}) \\~\\ \frac{a}{c}\,=\,\frac{\sqrt{10\,\cdot\,135}}{\sqrt{21\,\cdot\,8}} \,=\,\frac{\sqrt{2\cdot5\cdot5\cdot3\cdot3\cdot3}}{\sqrt{3\cdot7\cdot2\cdot2\cdot2}} \,=\,\frac{\sqrt{2}\cdot\sqrt{5\cdot5}\cdot\sqrt{3\cdot3}\cdot\sqrt{3}}{\sqrt{3}\cdot\sqrt{7}\cdot\sqrt{2\cdot2}\cdot\sqrt{2}} \,=\,\frac{\sqrt{5\cdot5}\cdot\sqrt{3\cdot3}}{\sqrt{7}\cdot\sqrt{2\cdot2}} \\~\\ \frac{a}{c}\,=\,\frac{5\,\cdot\,3}{2\sqrt{7}} \,=\,\frac{15\sqrt7}{14} \)
Find \($\frac{a}{c}$\)
Given : \($\frac{a}{b} = \frac{\sqrt{10}}{\sqrt{21}}$ \) \($\frac{b}{c} = \frac{\sqrt{135}}{\sqrt{8}}$\)
b = √(21/10) a
b = √(135/ 8) c
Which implies that
√(21/10) a = √(135/ 8) c ⇒
a / c = √(135/ 8) / √(21/10)
a / c = √ [ ( 135 * 10) / (21 * 8) ] = √ [ (45 * 5) / (7 * 4) ] = 15 / [ 2√7 ] =
15√7 / 14