Given \(f(x) = \frac{\sqrt{x-1}}{x-2}\), what is the smallest possible integer value for x such that f(x) has a real number value?
Realize that if the value of x is less than 1, that causes the numerator to be the square root of an imaginary(since 0-1 would be -1), which is clearly non-real. The smallest possible integer value for x then becomes 1.
