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Given \(f(x) = \frac{\sqrt{x-1}}{x-2}\), what is the smallest possible integer value for x such that f(x) has a real number value?

 May 3, 2020
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Realize that if the value of x is less than 1, that causes the numerator to be the square root of an imaginary(since 0-1 would be -1), which is clearly non-real. The smallest possible integer value for x then becomes 1.

 May 5, 2020
edited by jfan17  May 5, 2020
edited by jfan17  May 5, 2020

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