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The squares of three positive integers are in arithmetic progression, and the third integer is 12 more than the first.  Find the three integers.

 Dec 8, 2019

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 #1
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I will give the answer courtesy of a short computer code. Cphill will give an algebraic solution:


a=1; b=13;c= b-a; if(c==12, goto4, goto6);d=2#((b^2- a^2)/2 + a^2);printd,a,b; a++;b++;if(a<1000, goto2, 0)


The number are:
2^2 , 10^2, 14^2
4,      100,    196

 Dec 8, 2019
 #1
avatar
+1
Best Answer

I will give the answer courtesy of a short computer code. Cphill will give an algebraic solution:


a=1; b=13;c= b-a; if(c==12, goto4, goto6);d=2#((b^2- a^2)/2 + a^2);printd,a,b; a++;b++;if(a<1000, goto2, 0)


The number are:
2^2 , 10^2, 14^2
4,      100,    196

Guest Dec 8, 2019

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