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The sum of the perimeters of two equilateral triangles is 45 inches, and the area of the larger one is 16 times the area of the smaller one. What is the area, in square inches, of the larger triangle? 

Guest Mar 20, 2018
 #1
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Since  the larger triangle is 16 times that of the smaler, its side is = √16  =  4 times as much

 

So.....let the side of the smaller  = x

And the side of the larger  is 4x

 

And we have

3x + 3(4x) = 45

15x = 45

x = 3

 

So  the sidee of the larger  is  4(3)  = 12

 

And its area  =   (1/2)(12^2) (√3 / 2)   =  144√3 / 4   =   36√3  in^2

 

 

cool cool cool

CPhill  Mar 20, 2018
edited by CPhill  Mar 20, 2018

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