Given that log_{4n} (40*sqrt(3)) = log_{2n} (45), find n^3.
set log4n403–√=log3n45=tlog4n403=log3n45=t, thus
{4tnt=403–√3tnt=45{4tnt=4033tnt=45
we have
(43)t=83–√9=833–√⟹t=32(43)t=839=833⟹t=32
finally
8n32=403–√8n32=403
then
n3=75
