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Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR = 8. Find XY^2.

 Feb 17, 2020
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Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR = 8. Find XY^2.

SR = 10

YR = 8

YS = 6

Angle SYR = 90°

Angle RSY = ?         tan(RSY) = YR / YS   ∠ RSY = 53.13° 

LY = cos(53.13°) * YS = 3.6

LS = sqrt [(YS)2 - (LY)2] = 4.8

YN = SP + 2 * LS = 19.6

NX = SR - 2 * LY = 2.8

XY2 = YN2 + NX= 392    indecision

 

 Feb 17, 2020
edited by Dragan  Feb 17, 2020

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