A particular right square-based pyramid has a volume of 63,960 cubic meters and a height of 30 meters. What is the number of meters in the length of the lateral height (AB) of the pyramid? Express your answer to the nearest whole number.
+605 Let the side length of the base be $s$. Then $\frac{1}{3}s^2\cdot 30=63960$. Solve for $\sqrt{s^2+30^2}$.
