Write in the form $a \sqrt b$, where $a$ and $b$ are positive integers: \[\frac{1}{\sqrt{2}} +\frac{3}{\sqrt{8}} + \frac{6}{\sqrt{32}}.\]
The expression is equal to 4*sqrt(2).
\(\frac{1}{\sqrt{2}} +\frac{3}{\sqrt{8}} + \frac{6}{\sqrt{32}}\\ = \frac{\sqrt{32}}{\sqrt{32}} \times \left( \frac{1}{\sqrt{2}} +\frac{3}{\sqrt{8}} + \frac{6}{\sqrt{32}}\right) \)
now expand the bracket and simplify.