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Write in the form $a \sqrt b$, where $a$ and $b$ are positive integers: \[\frac{1}{\sqrt{2}} +\frac{3}{\sqrt{8}} + \frac{6}{\sqrt{32}}.\]

 Dec 20, 2021
edited by Guest  Dec 20, 2021
 #1
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The expression is equal to 4*sqrt(2).

 Dec 20, 2021
 #2
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\(\frac{1}{\sqrt{2}} +\frac{3}{\sqrt{8}} + \frac{6}{\sqrt{32}}\\ = \frac{\sqrt{32}}{\sqrt{32}} \times \left( \frac{1}{\sqrt{2}} +\frac{3}{\sqrt{8}} + \frac{6}{\sqrt{32}}\right) \)

 

now expand the bracket and simplify.

 Dec 20, 2021

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