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There are 5 girls and 5 boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.

If Anita is one of the club members, what fraction of all games at the tournament does Anita play in? Enter your answer as a fraction in simplified form.

SmartMathMan  Jan 17, 2018
 #1
avatar+86890 
+1

Total matches  =

 

9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1  =   45

 

Anita plays every other girl once  =  4 matches and every boy once = 5 matches...so

 

[ 4 + 5 ] /  45  =     9/45   =   

 

1/5

 

 

cool cool cool

CPhill  Jan 17, 2018

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