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Please solve!!! I had a lot of trouble with this problem.

 Dec 3, 2016
 #1
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√5 * (1/5)3x + 6.5 ≤ 0.2x(x + 4)     and we can write this as

 

√5 * (1/5)3x + 6.5 ≤ (1/5)x(x + 4)   let's just set this equal  and solve for x......

 

√5 *(1/5)3x + 6.5 = (1/5)x(x + 4)    divide both sides by (1/5)3x + 6.5

 

√5   = (1/5)x(x + 4) / (1/5)3x + 6.5    and we can write this as

 

√5  = (1/5)[ x (x + 4) - 3x - 6.5]       simplify the exponent

 

√5  = (1/5) [ x^2 + 4x - 3x - 6.5]

 

√5  = (1/5) [ x^2 + x - 6.5]     and we can write

 

5^(1/2)  =  (5^-1)^ [ x^2 + x - 6.5]      simplify, again

 

5^(1/2)  = (5)^ [-x^2 - x + 6.5]      note....now we can solve for the exponents since the bases are equal

 

(1/2)  = -x^2 - x + 6.5      multiply through by 2

 

1  = -2x^2 - 2x + 13        rearrange

 

2x^2 + 2x - 12  =  0     divide through by 2

 

x^2 +  x - 6  =  0     factor

 

(x + 3) ( x - 2)  = 0       setting each factor to 0, we have that

 

x = -3   or x = 2

 

Going back to the original inequality....our answers will either  come from these two intervals (inf, -3] U [2, inf)     or from this interval   [-3, 2] 

 

We can see if the last interval makes our original problem true by testing 0......if it makes the original problem true.....this is the solution interval

 

√5 * (1/5)3(0) + 6.5 ≤ 0.20(0 + 4)     ????

 

√5 * (1/5)^6.5 ≤   1   ??????

 

≈ 0.000143108... ≤  1    and this is true....so...the answer is    -3 ≤ x ≤  2

 

Note:   WolframAlpha confirms our solution  :  

 

https://www.wolframalpha.com/input/?i=%E2%88%9A5+*+(1%2F5)%5E%5B3x+%2B+6.5%5D%C2%A0%E2%89%A4+0.2%5E%5Bx(x+%2B+4)%5D

 

 

 

cool cool cool

 Dec 3, 2016

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