Distance between Train 1 and Train 2 = 95 miles. Average speed of Train 1 = 45 mph. Average speed of Train 2 = 60 mph. If both trains leave at the same time and travel toward each other but on parallel tracks, in how much time will their engines be opposite each other? (Hint: When the engines are opposite each other, together the trains will have traveled 95 miles. Their relative speed of travel is the sum of their respective speeds, or 105 mph.)
+37093 Maybe a little simpler:
Since they gave you the realtive speed as 105 mph and the distance travelled as 95 miles
95 miles/105 mph = .90476 h (as we found starting in 2nd step of prior solution)
+37093 Train a travels 45 mph x t
Train b travels d - 60 x t where d = 95 miles (given)
45t = 95-60t
105t = 95
t = 95/105 = .90476 hours (54.2857 minutes)
Check 45 (.90476) + 60(.90476) =? 95
95 = 95 Check!
+37093 Maybe a little simpler:
Since they gave you the realtive speed as 105 mph and the distance travelled as 95 miles
95 miles/105 mph = .90476 h (as we found starting in 2nd step of prior solution)
