If \( f(x) = \begin{cases} 2x-5 &\quad \text{if } x \ge 3, \\ -x + 5 &\quad \text{if } x < 3, \end{cases} \) then for how many values of x is f(f(x)) = 3?
The equation f(f(x)) = 3 has one solution.
+865 
