Graph a sine function whose amplitude is 4, period is pi, Midline is y= -3, and y- intercept is (0, -3). The graph is not a reflection of the parent function over the x axis. The first point Must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point
+140 Period = 4pi
T = 4pib = 2pi/T = 2pi/(4pi) = 1/2 = 0.5
Amplitude = 2a = 2
Midline: y = 3
d = 3
y-intercept: (0,3)
The function is a reflection of its parent function over the x-axis, so 'a' is negative meaning a = -2 instead of a = 2
The function is
y = a*sin(bx-c)+d
y = -2*sin(0.5x-0)+3
y = -2*sin(0.5x)+3
+129849 We have the form
y = A sin (Bx + C ) + D
A = the amplitude = 4
B = the number of periods in 2pi....so ...B = 2pi / period = 2pi/pi = 2
C is the phase shift....there is none....so....C = 0
D = the shift up / down = -3
So.....the equation is
y = 4sin (2x) - 3
Here is the graph : https://www.desmos.com/calculator/67jvpq3xip
