A bag contains 7 red, 5 orange, and 6 green jellybeans. What is the probability of reaching into the bag and randomly withdrawing 12 jellybeans such that the number of red ones is 6, the number of orange ones is 4, and the number of green ones is 2?
\(p = \dfrac{\dbinom{7}{6}\dbinom{5}{4}\dbinom{6}{2}}{\dbinom{18}{12}} = \dfrac{25}{884}\)
