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5

Σ i ^ (i+2)

i=3

 Jun 14, 2019
edited by ProffesorNobody  Jun 14, 2019
 #1
avatar+8778 
+2

\(\sum\limits_{i=3}^5i^{(i+2)}\ =\ 3^{(3+2)}+4^{(4+2)}+5^{(5+2)}\\~\\ \phantom{\sum\limits_{i=3}^5i^{(i+2)}}\ =\ 3^5+4^6+5^7\\~\\ \phantom{\sum\limits_{i=3}^5i^{(i+2)}}\ =\ 243+4096+78125\\~\\ \phantom{\sum\limits_{i=3}^5i^{(i+2)}}\ =\ 82464\)_

 Jun 14, 2019
 #2
avatar+25 
-4

Thank You! :P

ProffesorNobody  Jun 14, 2019

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